Calculating Time Needed for 10 m/s Increase

[Aamurs]

Homework Statement

distance= z + b*time + x*(time^2) + y*(time^3)

x=0,2m/s^2
y=0,15m/s^3

I have to calculate after how long time the speed has increased by 10 m/s

The Attempt at a Solution

I have no idea what to do with m/s^3

 

[SteamKing]

Your problem statement is unclear.

Please post the complete and exact wording of the problem, as it appears in your text or was otherwise supplied to you.

 

[Aamurs]

Yeah, sorry, I didn't write the formula correctly that was given in this exercise.. I edited the OP.
distance= z + b*time + x*(time^2) + y*(time^3)

z is some distance
b is starting speed

I have really bad English when it comes to terminology, so I hope you can understand now.

 

[Orodruin]

How is the velocity related to the distance travelled?

 

[HalfLostAndSearching]

I understand that the given equation represents a position-time relationship, where z represents the initial position, b represents the initial velocity, x represents the acceleration, and y represents the rate of change of acceleration. In this case, the acceleration is increasing at a rate of 0.2 m/s^2 and the rate of change of acceleration is 0.15 m/s^3.

To calculate the time needed for the speed to increase by 10 m/s, we can use the formula for velocity, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. In this case, we know that the initial velocity is 0 m/s, the acceleration is 0.2 m/s^2, and we want the final velocity to be 10 m/s.

So, we can rearrange the formula to solve for time, t = (v-u)/a. Plugging in the values, we get t = (10 m/s - 0 m/s)/0.2 m/s^2 = 50 seconds.

Therefore, it would take 50 seconds for the speed to increase by 10 m/s, given the initial conditions and the rate of change of acceleration. I would also recommend double-checking the units to ensure they are consistent throughout the equation.