Calculating Torque Absorbed: Vehicle Deceleration from 100 km/hr to 50 km/hr

[sulhil]

a vehicle is moving at 100 km/hr. the foot is lifted off the accelerator, and the vehicle decelerates, if a mechanism is introduced to absorb the toque from the differential gear(bevel ring gear). and it decelerates the vehicle from 100 km/hr to 50 km/hr. what would be the amount of torque absorbed.

it is kind of a similar scenario where a flywheel under motion is decelerated and torque is produced.
in the vehicle scenario am not sure how to use the moment of inertia

 

[mfb]

I think without additional data about the setup, it is impossible to answer the question.

 

[sulhil]

well let's say a vehicle is moving at 100 km/hr, and the foot is raised off the accelerator, it is leveled road . and the vehicle is aloved to decelerate. at this point the bevel ring gear of the diffrentil of the vehicle would still countinue to rotate as the wheels are rotating. how could i find the torque of the rotating bevil ring gear ??

 

[russ_watters]

You need to know the mass of the car and gear ratio.

 

[sulhil]

well i do have the weight of the vehicle as well as the gear ratio

could u give me some calculations i could use ??

 

[mfb]

Without additional data, there is nothing you could use in a calculation.

 

[russ_watters]

Acceleration = torque at the wheels / wheel radius / mass

 

[sulhil]

could u please elaborate a bit more, as in its the acceleration of the vehicle we r toking here, and is it the mass of the vehicle itself tht we are talking ??

 

[russ_watters]

Yes to both.

 

[sulhil]

thanks a lot for ur input, could u give me any reference to the formula u have supplied me with ,
and is it
acceleration = [torque at the wheels/wheel radios]/mass
or
acceleration= torque at the wheels /[wheel radios/mass]