- #1
mechdesignron
- 9
- 0
I would like someone to confirm, comment on my understanding of torque calculations of a rotating body.
Formula: [tex]T[/tex]=[tex]I[/tex][tex]\alpha[/tex]
[tex]I[/tex]=LB-FT2 (1366.5) Known
[tex]\alpha[/tex]=Rad/s2(43.33)
Angular acceleration from 600-0 RPM in 1.45 sec
Now I believe I need to divide by 32.2 ft/s2 (accelleration of gravity)
This should give me FT-Lbs torque required to (stop) 1366.5 inertia in 1.45 sec.
Please confirm that this is correct with units.
Thank You
Ron
Formula: [tex]T[/tex]=[tex]I[/tex][tex]\alpha[/tex]
[tex]I[/tex]=LB-FT2 (1366.5) Known
[tex]\alpha[/tex]=Rad/s2(43.33)
Angular acceleration from 600-0 RPM in 1.45 sec
Now I believe I need to divide by 32.2 ft/s2 (accelleration of gravity)
This should give me FT-Lbs torque required to (stop) 1366.5 inertia in 1.45 sec.
Please confirm that this is correct with units.
Thank You
Ron