Calculating Torque of Diver on Board: 1.82 m for 56 kg

[needhelp83]

How far out on a diving board (Fig.12-52 of your text) would a 56-kg diver have to be to exert a torque of 1000 m.N on the board, relative to the left support post?

1000 m*N= (56 kg)(9.8 m/s2)x
1000 m*N=548.8x
x=1.82 m

He would have to walk out 1.82 m on the board.

Is this done correctly?

 

[rsk]

yes, as far as I can tell!

 

[kyle8921]

Yes, your calculations are correct. To calculate torque, we use the formula T = Fd, where T is the torque, F is the force applied, and d is the distance from the pivot point. In this case, the pivot point is the left support post. So, the torque exerted by the diver can be calculated as T = (56 kg)(9.8 m/s2)(x), where x is the distance from the pivot point to the diver. Setting this equal to 1000 m*N and solving for x, we get x = 1.82 m. This means that the diver would need to walk out 1.82 m on the diving board to exert a torque of 1000 m*N on the board.