- #1
Martin_79
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Homework Statement
Hi All,
I am new to this forum and have a question for which I need some assistance. My knowledge about this subject is limited, but I need te following:
For a project we need to specify the torque required to uprighten a structure when rotated to a certain angle. The structure is located at a distance where the torque can be applied.
I know how to calculate the torque exterted by the structure at an angle. However, I presume that, when the counteracting torque is to be applied at a certain distance, the calculation would be different. Additionally, the pipe will twist as a result of the structure rotation, but how does this influence the required torque to uprighten the structure?
Your help is greatly appreciated!
Regards,
Martin
Homework Equations
W(torque) = F (force) * a (arm)
a = sin (α) * distance CoG (relative to pipe centreline)
The Attempt at a Solution
F = 16 tonnes (156.96 kN)
Distance between CoG and pipe centreline = 0.5 m
α = 15 degrees (0.2618 radians)
a = sin (15) * 0.5 = 0.1294 m
W = 156.96 kN * 0.1294 m = 20.3 kNm
From this point onwards I do not know how and if additional calculations are required which include the twisting pipeline. The properties of the pipeline are:
Outer diameter = 300 mm
Wall thickness = 20 mm
Material = steel (E-modulus = 207 GPa)
Poisson ratio = 0.3