Calculating Total Force on Diving Bell's Port

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In summary, the problem involves finding the magnitude of the total force on a flat, transparent, circular port of an evacuated spherical diving bell at a depth of 121 m in the ocean. The equation for total pressure is P(total)= ρgh+P(atm), and the area can be calculated using A=\piR^2. The atmospheric pressure may be neglected as it cancels out with the atmospheric pressure inside the bell. However, to be more realistic, the atmospheric pressure should be added to the water pressure since the sphere is evacuated.
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Homework Statement



An evacuated spherical diving bell containing a camera is in the ocean at a depth of 121 m. It has a flat, transparent, circular port with a diameter of 19.7 cm. Find the magnitude of the total force on the port (use ρseawater) = 1025 kg/m3).

Homework Equations



P(total)= ρgh+P(atm)
A=[tex]\pi[/tex]R^2


The Attempt at a Solution



I know that you need to find the total pressure on the bell. And then i think you have to subtract that total pressure from atmospheric pressure. this is what i have been doing and it is not working correctly. does anyone have any ideas?

Thanx!
 
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  • #2
Force = pressure x area. You know the pressure of the water at that depth, since density is known. Rest is easy. Atm presssure may be neglected.
 
  • #3
Just to amplify what Shooting star is saying, the reason you can neglect atmospheric pressure is not because it is terribly small. It's about ten percent of the seawater pressure, but because you should probably assume there is also atmospheric pressure inside of the bell, so it cancels. Just use the rhoseawater they gave you together with the area.
 
Last edited:
  • #4
Total force on the port:

pressure/area from seawater on one side
pressure/area from 1atm on the other side
 
  • #5
Hi Dick,

The problem specifically states that the sphere has been evacuted. So, inside is almost vacuum.

To be realistic then, P_atm should be added to the water pressure, since 1/10 of the water pressure is not really negligible.
 
  • #6
Shooting star said:
Hi Dick,

The problem specifically states that the sphere has been evacuted. So, inside is almost vacuum.

To be realistic then, P_atm should be added to the water pressure, since 1/10 of the water pressure is not really negligible.

In that case, yes, it should. Sorry, I should read more carefully!
 

Related to Calculating Total Force on Diving Bell's Port

What is a diving bell and how does it work?

A diving bell is a type of underwater vessel that is used to transport divers to great depths. It works by trapping air inside the bell, creating a pocket of air for the divers to breathe in while they are submerged.

What factors affect the total force on a diving bell's port?

The total force on a diving bell's port is affected by the depth of the dive, the weight of the diving bell and its contents, and the water pressure at that depth.

How do you calculate the total force on a diving bell's port?

The total force on a diving bell's port can be calculated by multiplying the water pressure at that depth by the surface area of the port.

Why is it important to calculate the total force on a diving bell's port?

It is important to calculate the total force on a diving bell's port because it allows for the proper design and construction of the diving bell to ensure the safety of the divers inside.

What are some potential risks associated with miscalculating the total force on a diving bell's port?

Miscalculating the total force on a diving bell's port can result in the diving bell being unable to withstand the water pressure at a certain depth, leading to structural damage or collapse. This can put the divers inside at risk of injury or even death.

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