- #1
physics_newb
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Homework Statement
A train is 120m long. Gaurav was standing 200m from the front of the train when it began to accelerate uniformly from rest. He noticed that the front of the train was moving at 8.00m/s when it passed him. How fast would the back of the train be going when it passed Gaurav?
Homework Equations
The Attempt at a Solution
Distance from front=200m
v1=0.00m/s
v2=8.00m/s
Step 1
a=?
V2^2= v1^2 + 2ad
a= (((V2^2-v1^2 ))/2)/d
a=(((8^2-0^2 ))/2)/200
a=(64/2)/200
a=32/200
a=0.16m/s/s
Step 2
t=?
t=v2/a
t=8/0.16
t=50s
after that last part I am completely lost...