Calculating Travel Time for Light in an Optical Fiber

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In summary, the conversation discusses an optical fiber with a central plastic core and plastic sheath, and the different travel times for light along the central axis and at critical angles. The difference in travel times for these two routes can be calculated using the formula t = n1^2*L/(n2*c) - n1*L/c.
  • #1
chrisliu1234
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Figure 35-57 shows an optical
fiber in which a central plastic
core of index of refraction n1 
1.58 is surrounded by a plastic
sheath of index of refraction n2 
1.53. Light can travel along different
paths within the central
core, leading to different travel times through the fiber.This causes an
initially short pulse of light to spread as it travels along the fiber,
resulting in information loss. Consider light that travels directly along
the central axis of the fiber and light that is repeatedly reflected at the
critical angle along the core–sheath interface, reflecting from side to
side as it travels down the central core. If the fiber length is 300 m,
what is the difference in the travel times along these two routes?

I know that I need to use t=L/v1=n1*L/c which becomes t=L/v1*cos(theta)=n1*L/(c*sqrt(1-(sin(theta)/n1)^2), but now I am stuck trying to figure the time for the question.
 
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  • #2
chrisliu1234 said:
Figure 35-57 shows an optical
fiber in which a central plastic
core of index of refraction n1 
1.58 is surrounded by a plastic
sheath of index of refraction n2 
1.53. Light can travel along different
paths within the central
core, leading to different travel times through the fiber.This causes an
initially short pulse of light to spread as it travels along the fiber,
resulting in information loss. Consider light that travels directly along
the central axis of the fiber and light that is repeatedly reflected at the
critical angle along the core–sheath interface, reflecting from side to
side as it travels down the central core. If the fiber length is 300 m,
what is the difference in the travel times along these two routes?

I know that I need to use t=L/v1=n1*L/c which becomes t=L/v1*cos(theta)=n1*L/(c*sqrt(1-(sin(theta)/n1)^2), but now I am stuck trying to figure the time for the question.

Hi chrisliu1234! Welcome to MHB! (Smile)

Let's start with $t=\frac{n_1 L}{c}$ for the time to travel along the central axis.
Did you find the corresponding time?

As for the light traveling at critical angles, you're supposed to deduce a formula without theta.
Is that perhaps where your problem is? (Wondering)
 
  • #3
I like Serena said:
Hi chrisliu1234! Welcome to MHB! (Smile)

Let's start with $t=\frac{n_1 L}{c}$ for the time to travel along the central axis.
Did you find the corresponding time?

As for the light traveling at critical angles, you're supposed to deduce a formula without theta.
Is that perhaps where your problem is? (Wondering)

So does change in time = t zigzag - t direct = n1^2*L/n2*c - n1*L/c?
 
  • #4
chrisliu1234 said:
So does change in time = t zigzag - t direct = n1^2*L/n2*c - n1*L/c?

That looks right yes. (Nod)
 

FAQ: Calculating Travel Time for Light in an Optical Fiber

What is interference?

Interference is a phenomenon in which two or more waves meet and interact with each other, resulting in a change in their amplitude, frequency, or direction of propagation.

What are the types of interference?

There are two types of interference: constructive and destructive. Constructive interference occurs when two waves meet and their amplitudes add together, resulting in a larger amplitude. Destructive interference occurs when two waves meet and their amplitudes cancel each other out, resulting in a smaller amplitude.

What causes interference?

Interference is caused by the superposition of waves, which occurs when two or more waves overlap in space and time. This can happen when waves are emitted from the same source, or when waves are reflected or refracted.

How does interference affect sound?

In sound, interference can result in an increase or decrease in loudness, as well as changes in the quality of the sound. This is because the superposition of waves can either amplify or cancel out certain frequencies, altering the overall sound.

What are some real-life examples of interference?

Interference can be observed in many natural phenomena, such as the colors seen in soap bubbles and oil slicks, the patterns created by overlapping ripples in water, and the sound produced by musical instruments. It is also used in technology, such as in noise-cancelling headphones and radio communication.

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