- #1
baylorbelle
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A proton with a kinetic energy of 4.6×10−16 J moves perpendicular to a magnetic field of 0.26 T. What is the radius of its circular path?
I know the formula is r=mv/qb. the only thing not given is v. So my question is how do I get v from Joules? I know 1 Joule=1N/m, and that N=ma, but I don't know how to get velocity from that. Any help on that part would be greatly appreciated : )
I know the formula is r=mv/qb. the only thing not given is v. So my question is how do I get v from Joules? I know 1 Joule=1N/m, and that N=ma, but I don't know how to get velocity from that. Any help on that part would be greatly appreciated : )