- #1
bigtymer8700
- 40
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A bicycle racer is going downhill at 11.0m/s when, to his horror, one of his 2.25kg wheels comes off when he is 75.0m above the foot of the hill. We can model the wheel as a thin-walled cylinder 85.0cm in diameter and neglect the small mass of the spokes.
I need to get the velocity at the bottom of the hill and KEtotal at the bottom
I know Kf=1/2Mv^2 + 1/2(I)w^2
Vo=11m/s
M=2.25kg
r=.425m
I know I=MR^2
I=.4064kg*m^2
would you use Ki+Ui=Kf+Uf to get w? or is there another way?
I need to get the velocity at the bottom of the hill and KEtotal at the bottom
I know Kf=1/2Mv^2 + 1/2(I)w^2
Vo=11m/s
M=2.25kg
r=.425m
I know I=MR^2
I=.4064kg*m^2
would you use Ki+Ui=Kf+Uf to get w? or is there another way?