Calculating Wavelengths in de Broglie's Standing Wave Condition

In summary, the de Broglies standing wave condition states that an integral number of wavelengths must fit into the circumference of the Bohr orbit. The question asks for the number of "internal wavelengths" in the fourth exited state of Be3+, which is equivalent to asking for the value of n in the equation n lambda = 2 pi r. By using the information given, we can determine that n = 5, disregarding the specific atom and the circumference of the orbit. This means that there are 5 internal wavelengths in the fourth exited state of Be3+.
  • #1
powerof1004
9
0

Homework Statement



de Broglies standing wave condition demands that an inegral number of wavelengths fit into the circumference of the Bohr orbit. How many "interal wavelengths" are there in the fourth exited state of Be3+?

Homework Equations



n lambda = 2 pi r

The Attempt at a Solution



i tried to solve using the equation above but was confused on lambda and r, both unknowns.

n = 5 because of fourth excited state i think
not sure what use the charge is in this problem...
 
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  • #2
powerof1004 said:

Homework Statement



de Broglies standing wave condition demands that an inegral number of wavelengths fit into the circumference of the Bohr orbit. How many "interal wavelengths" are there in the fourth exited state of Be3+?

Homework Equations



n lambda = 2 pi r

The Attempt at a Solution



i tried to solve using the equation above but was confused on lambda and r, both unknowns.

n = 5 because of fourth excited state i think
not sure what use the charge is in this problem...

It seems to me the question is asking for the number of wavelengths, not a value/size of each wavelength. You had answered that. Perhaps I misread, or there was more to the question than you wrote ??
 
  • #3
Yeah, I think you just answered your own question. As you said, there are 5 internal wave-lengths.
 
  • #4
SpecialKM said:
Yeah, I think you just answered your own question. As you said, there are 5 internal wave-lengths.

really??
but i just used one piece of info and totally disregarded the rest and didnt use any formulas...
 
  • #5
powerof1004 said:
really??
but i just used one piece of info and totally disregarded the rest and didnt use any formulas...

As I said, the [part of the] question you posted did not include any information which you feel you have "totally disregarded" ?

EDIT: And don't get hung up on always wanting to use a formula.
 
  • #6
I didnt use Be3+ or any of the information of the circumference. I just came to n=5 due to fourth excited state.
wouldn't that be disregarding the other pieces of information?
 
  • #7
powerof1004 said:
I didnt use Be3+ or any of the information of the circumference. I just came to n=5 due to fourth excited state.
wouldn't that be disregarding the other pieces of information?

If the question had said:

"How many "interal wavelengths" are there in the fourth exited state"

people may be wondering "How many "fourth exited state of what?"

I think the use of Be3+ is just there because some atom had to be.
 
  • #8
Wow than this was a much simpler problem than i thought it would be
Thanks Guys
 

FAQ: Calculating Wavelengths in de Broglie's Standing Wave Condition

What is De Broglie's standing wave?

De Broglie's standing wave is a concept in quantum mechanics proposed by French physicist Louis de Broglie in the early 20th century. It describes the wave-like behavior of matter particles, such as electrons, and suggests that they have both particle and wave-like properties.

How does De Broglie's standing wave relate to the wave-particle duality?

De Broglie's standing wave is one of the key concepts that supports the wave-particle duality theory. It suggests that all matter particles have a corresponding wavelength and exhibit wave-like behavior, similar to light particles.

What is the mathematical equation for De Broglie's standing wave?

The mathematical equation for De Broglie's standing wave is λ = h/mv, where λ is the wavelength, h is Planck's constant, m is the mass of the particle, and v is the velocity of the particle.

How does De Broglie's standing wave explain the behavior of electrons in an atom?

De Broglie's standing wave helps explain the quantized energy levels of electrons in an atom. The standing wave created by the electron's wavelength corresponds to a specific energy level, and as the electron moves, the standing wave changes, causing the electron to jump between energy levels.

What are some real-world applications of De Broglie's standing wave?

De Broglie's standing wave has been used to develop technologies such as electron microscopes, which use the wave-like behavior of electrons to produce detailed images of tiny structures. It has also been used in the development of quantum computers, which utilize the wave-particle duality of matter particles to process information.

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