Calculating Work: 6.75kg Bucket Raised 4m

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In summary, the correct solution for part (b) is -265 J and the book's solution of -0.900 J is incorrect.
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zrbecker
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Homework Statement


An old oaken buck of mass 6.75 kg hangs in a well at the end of a rope. The rope passes over a frictionless pulley at the top of the well, and you pull horizontally on the end of the rope to raise the bucket slowly a distance of 4.00m. (a) How much work do you do on the bucket in pulling it up? (b) How much work does gravity do on the bucket? (c) What is the total work done on the bucket?

Homework Equations



W = Fscos(phi)

The Attempt at a Solution



For (b) my solution was

F = mg = 6.75 * 9.81
s = 4.00
phi = 180 degrees (gravity pulls down, bucket moves up)

So W = 6.75 * 9.81 * 4.00 * -1 = -265 J

The book says it is -0.900 J

EDIT: Figured it out. Book is wrong. Found a solutions manual.
 
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  • #2


I can confirm that your solution for part (b) is correct. The work done by gravity on the bucket is indeed -265 J. It is important to note that the negative sign indicates that the work is done against gravity, as the bucket is moving in the opposite direction of the force of gravity.

I would recommend double checking the solutions manual you referenced to see if there may have been a mistake or typo in their answer. It is always important to double check and verify information, especially in the scientific community. Keep up the good work!
 

Related to Calculating Work: 6.75kg Bucket Raised 4m

1. How do you calculate work in this scenario?

In order to calculate work, you need to use the formula W = F x d, where W is the work done, F is the force applied, and d is the distance over which the force is applied. In this scenario, we have a force of gravity acting on the 6.75kg bucket, and the distance it is raised is 4m, so we can use the formula to calculate the work done.

2. What is the force acting on the bucket?

The force acting on the bucket is the force of gravity, which is equal to the mass of the bucket (6.75kg) multiplied by the acceleration due to gravity (9.8m/s^2). This gives us a force of approximately 66.15N.

3. How do you convert the mass of the bucket from kilograms to newtons?

To convert kilograms to newtons, you can use the formula F = m x a, where F is the force in newtons, m is the mass in kilograms, and a is the acceleration due to gravity (9.8m/s^2). In this scenario, we can plug in the mass of the bucket (6.75kg) and calculate the force to be approximately 66.15N.

4. Is work dependent on the path of the object?

No, work is not dependent on the path of the object. Work is only dependent on the force applied and the distance over which the force is applied. In this scenario, as long as the bucket is raised 4m against the force of gravity, the work done will be the same regardless of the path taken.

5. What is the unit for work?

The unit for work is joules (J). One joule is equal to one newton-meter (N*m). In this scenario, the work done would be approximately 264.6J.

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