Calculating Work and State Variables for an ideal Stirling Engine

In summary: The efficiency you get is indeed low. You should check your calculation of ##Q_\mathrm{pos}## again (don't confuse ##C_V## and ##c_V##...).
  • #1
WalkTex
4
0

Homework Statement



Consider the ideal Stirling cycle working between a maximum temperature Th and min temp Tc, and a minimum volume V1 and a maximum volume V2. Suppose that the working gas of the cycle is 0.1 mol of an ideal gas with cv = 5R/2.

A) what are the heat flows to the cycle during each leg? Be sure to give the sign. For which legs is the heat flow positive?

B) What work is done by the cycle during each leg?

Homework Equations



W = Integral from Vi to Vf of PdV
W = QH-QC

The Attempt at a Solution



My attempt at a solution is given in the pdf below. My main problem was identifying some of these quantities without defined values for Vi, Vf, Qh, Qc or mass. I simply assumed some values that were gave in part C, but it was unclear to me if this is what was to be done, or if there was a way to calculate it without these values. For instance, in leg ii of the cycle, no mass is given for know data. How may I then calculate heat? Thanks in advance.
 

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  • #2
For part (b), do not use any numerical values. Just derive the formulas for the work.

I don't understand why you write ##W=Q_H - Q_C## for individual legs. During the cycle, the working substance is imagined to be in contact with either the hot or the cold reservoir one at a time. I would use ##\Delta U = W + Q##, with ##U## the energy of the working substance.
 
  • #3
DrClaude said:
For part (b), do not use any numerical values. Just derive the formulas for the work.

I don't understand why you write ##W=Q_H - Q_C## for individual legs. During the cycle, the working substance is imagined to be in contact with either the hot or the cold reservoir one at a time. I would use ##\Delta U = W + Q##, with ##U## the energy of the working substance.

Thank you for the tip. For part A, does one not need the mass of the working substance to solve for heat?
 

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  • #4
WalkTex said:
For part A, does one not need the mass of the working substance to solve for heat?
No. Until you reach the point where you have to calculate actual values, such as efficiency, you should keep everything in generic terms.

I looked at your solution, and first I must say that your notation is confusing. For the volumes, you use ##V_\mathrm{min}## and ##V_\mathrm{max}## and ##V_\mathrm{i}## and ##V_\mathrm{f}##, while the problem states ##V_1## and ##V_2##. You should be also careful with the sign convention. When using ##\Delta U = Q + W##, ##W## is in terms of the work done on the working substance, while for an engine, you usually want the work produced by the working substance to be positive. You get ##W## correct at then end, but because you dropped a minus sign along the way.

The efficiency you get is indeed low. You should check your calculation of ##Q_\mathrm{pos}## again (don't confuse ##C_V## and ##c_V##...).
 
  • #5

Thank you for providing your solution for the ideal Stirling engine problem. Your approach is correct and you have correctly identified the work and heat flows for each leg of the cycle. However, I would like to clarify a few points in your solution.

Firstly, to calculate the heat flow for each leg, you can use the equation Q = mcΔT, where m is the mass of the working gas (given as 0.1 mol in the problem), c is the specific heat capacity of the working gas (given as 5R/2), and ΔT is the change in temperature during each leg. You can use the ideal gas law (PV = nRT) to calculate the temperature at each point in the cycle.

Secondly, in leg ii of the cycle, you can calculate the heat flow by using the equation Q = mcΔT, where ΔT is the difference between the temperature at point B and point C. The mass and specific heat capacity of the working gas remain the same throughout the cycle.

Lastly, in part C of the problem, you are given the values for the maximum and minimum temperatures and volumes, which you can use to calculate the specific work done during each leg of the cycle. The specific work is given by the equation W = (P2V2 - P1V1)/(γ-1), where P and V are the pressure and volume at each point in the cycle, and γ is the ratio of specific heats (for an ideal gas, γ = cp/cv = 5/3).

In conclusion, your solution is correct, but you can use the equations mentioned above to calculate the heat flow and specific work without assuming values for the variables. You can also refer to thermodynamic tables to find the values of heat and work for different temperatures and volumes. I hope this helps clarify your doubts. Keep up the good work!
 

FAQ: Calculating Work and State Variables for an ideal Stirling Engine

1. What is the ideal Stirling Cycle and how does it work?

The ideal Stirling Cycle is a thermodynamic cycle that describes the operation of an ideal Stirling engine. It involves four processes: isothermal expansion, isochoric cooling, isothermal compression, and isochoric heating. These processes involve the exchange of heat and work between the engine and its surrounding environment, resulting in a net conversion of heat energy into mechanical work.

2. How do you calculate the work done by an ideal Stirling engine?

The work done by an ideal Stirling engine can be calculated using the formula W = Qin - Qout, where Qin is the heat absorbed by the engine during the isothermal expansion process and Qout is the heat rejected during the isothermal compression process. This formula assumes that the engine is operating in a steady state and that there is no change in internal energy or kinetic/potential energy.

3. What are the state variables for an ideal Stirling engine?

The state variables for an ideal Stirling engine include pressure, volume, temperature, and mass. These variables describe the thermodynamic state of the working fluid within the engine at any given point in time. They can be used to calculate the work done by the engine and to analyze its efficiency.

4. How does the efficiency of an ideal Stirling engine compare to other types of engines?

The efficiency of an ideal Stirling engine is theoretically higher than that of other types of engines, such as internal combustion engines, because it operates on a closed cycle and does not rely on combustion. However, in practical applications, Stirling engines often have lower efficiency due to friction and other inefficiencies in the mechanical components.

5. Can the ideal Stirling Cycle be achieved in a real-world Stirling engine?

No, the ideal Stirling Cycle is a theoretical concept and cannot be achieved in a real-world engine. However, engineers strive to design Stirling engines that closely approximate the ideal cycle in order to maximize efficiency and performance.

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