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DumSpiroSpero
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Homework Statement
A force F acts over the block as show in the figure. F have a constant magnitude, but has a variable direction. The direction of F, at any given instant, always is directed to the point P.
Evaluate the work done by the force F through the displacement d between the points R and M.
sin 37º = cos53º = 3/5; cos 37º = sin53º = 4/5.
Homework Equations
The Attempt at a Solution
I really can't solve this one. I tried to take only the horizontal axis ( $$F\cos(37º)$$ at R and $$F\cos(53º)$$ at M), because the vertical components are perpendicular to the displacement $$\vec{d}$$. However, since the force have a variable direction, I don't have any idea of how to evaluate the work done between R and M; the angle increases from 37º to 53º, but I don't know how to do that. I never faced any problem in which the force have a variable direction.
I would appreaciate any tips. Thanks!
Answer: $$W = \frac{5}{7}\cdot F \cdot d$$
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