Oddly enough your answer is correct. But I have no idea what you are doing.williamx11373 said:a horizontal force of 200 Newtons is applied to a 55 kg cart across a 10 meter surface. If the cart accelerates at 2 meters/second squared, then what is the work done by the force of friction as it acts to retard the motion of the cart ??
Work= FX
work= maX
55 kg x 2 x 10 = 1100 - 200 N = 900 Joules ??
The work done by friction can be calculated by multiplying the force of friction by the displacement of the cart in the direction of the force. In this case, the formula would be W = Fd, where W is the work done, F is the force of friction, and d is the displacement of the cart.
The unit of measurement for work done is joules (J). This is equivalent to a force of one newton acting over a distance of one meter.
The force of friction can be determined by using the formula Ff = μN, where Ff is the force of friction, μ is the coefficient of friction, and N is the normal force (equal to the weight of the cart in this case).
The work done by friction is negative. This is because the force of friction always acts in the opposite direction of the displacement, resulting in negative work.
No, the displacement is a necessary component in the calculation of work done by friction. Without the displacement, the value of work done cannot be determined.