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Jrlinton
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Homework Statement
A single force acts on a 3.3 kg particle-like object in such a way that the position of the object as a function of time is given by x = 2.1t - 1.4t2 + 1.7t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 4.8 s.
Homework Equations
Basic work formulas
The Attempt at a Solution
So i found the distance of the movement by plugging 4.8 for t and got 165.83 m, found the second derivative of the position formula to get the acceleration function, got 46.16m/s/s at 4.8s. I multiplied these quantities as well as the mass to get 25260.6 J. This was obviously wrong
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