Calculating Work for Orbital Transfer of a Satellite

In summary, the conversation discusses how to calculate the work required to move a satellite from one orbit to another using the formula for gravitational potential energy. The participants also clarify the use of the Earth's radius and the difference in total energies for the two orbits.
  • #1
seiferseph
102
0
How would i go about doing a problem like this?

A 1500 kg satellite is orbiting the Earth at a height of 250 km. How much work would it take to move it into an 800 km orbit?
 
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  • #2
Use the gravitational potential energy. If the radius increases, this energy will become less negative, ergo, the energy rises...

marlon
 
  • #3
The formula is [tex]- \frac{GMm}{R}[/tex]

G is the universal gravitational constant
M is the mass of the first object
m is the mass of the second object
r is the radius

be sure to treat the Earth as a point mass with all mass centered in that point. Thus, you will also need the Earth's radius...

marlon
 
  • #4
that is just the equation for gravitational potential energy at one point. wouldn't it have kinetic? and it asks for work in the question. also, its worth 10 marks, so i don't think it can be that simple.

i've done some where you take it off the surface and throw it into orbit, and i used

Etotal(orbit) = Epotential(surface) + W
 
  • #5
The total mechanical energy (KE + gravitational potential) that a body has is found,when solving the Kepler problem in CM,

[tex] \mbox{Tot \ E}=-G\frac{m_{body}M_{Earth}}{2a} [/tex]

,where "a" is the big semiaxis of the elliptical orbit.However,it can be proven really easliy that "a" goes to R (radius of orbit) for a circular orbit.

It's all u need to know.The work done is simply the variation in total energy of the body.

Daniel.
 
  • #6
dextercioby said:
The total mechanical energy (KE + gravitational potential) that a body has is found,when solving the Kepler problem in CM,

[tex] \mbox{Tot \ E}=-G\frac{m_{body}M_{Earth}}{2a} [/tex]

,where "a" is the big semiaxis of the elliptical orbit.However,it can be proven really easliy that "a" goes to R (radius of orbit) for a circular orbit.

It's all u need to know.The work done is simply the variation in total energy of the body.

Daniel.

isn't that just its total energy at that point? what is the work used to bring it up into a higher orbit? this is the equation my professor gave me for moving something from the surface up into an orbit: Etotal(orbit) = Epotential(surface) + W
 
  • #7
Mind that there's a trick here.The height is given wrt Earth's surface,while R in the formulas is the distance between the Earth's center & the orbit (the circle's radius).

So u need to add the mean Earth's radius

[tex] \bar{R}_{Earth}\simeq 6371 \ \mbox{Km} [/tex]

Daniel.


P.S.Of course,for consistency of units,u need to transform every length from Km to m...
 
  • #8
The sattelite is already in orbit...W is just the diff.between total energies...

Daniel.
 
  • #9
dextercioby said:
The sattelite is already in orbit...W is just the diff.between total energies...

Daniel.

so its just Etotal(2nd orbit) - Etotal(1st orbit)? using the equation you said, except using the larger value 800km for R for the 2nd orbit and smaller 250km for 1st orbit?
 
  • #10
Yeah,that's right...

Daniel.
 

FAQ: Calculating Work for Orbital Transfer of a Satellite

What is the force of gravity?

The force of gravity is the attractive force between two objects with mass. It is described by Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

How is gravity related to mass and distance?

Gravity is directly proportional to the product of the masses of two objects. This means that the larger the masses of the objects, the stronger the force of gravity between them. Additionally, gravity is inversely proportional to the square of the distance between the objects. This means that the farther the objects are from each other, the weaker the force of gravity between them.

What is the difference between mass and weight?

Mass is a measure of the amount of matter an object contains, while weight is a measure of the force of gravity acting on an object. Mass is constant regardless of the location, but weight can change depending on the strength of the gravitational field in that location.

How does gravity affect objects in free fall?

Objects in free fall experience a constant acceleration due to the force of gravity. This means that their velocity increases by 9.8 meters per second squared (on Earth) for every second they are in free fall. This is known as the acceleration due to gravity.

How does the shape of an object affect its gravitational pull?

The shape of an object does not affect its gravitational pull. As long as the mass and distance between the objects remain constant, the force of gravity will be the same. However, the distribution of mass within an object can affect its center of gravity, which can impact its stability and motion.

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