- #1
KedarMhaswade
- 35
- 6
- Homework Statement
- Calculate the temperature increase of 100 kg of brake material with an average specific heat of 800 J/kg⋅ºC if the material retains 10% of the energy from a 10,000-kg truck descending 75.0 m (in vertical displacement) at a constant speed. (see: https://openstax.org/books/college-physics-ap-courses/pages/14-2-temperature-change-and-heat-capacity)
- Relevant Equations
- Equating the loss of potential energy of the truck to the gain of the internal energy of the brake material seems alright, but is that what is required? What about friction and loss of heat to atmosphere during the descent?
The text gives the answer as 92ºC. The answer is arrived at by doing ##Q=Mgh=mc\Delta T##. But it is unclear to me if they are the same. I checked the coefficient of friction and it definitely seems to be considerable. Is the entire PE lost by the truck going to result in increasing the temperature of the brake material, or is it only 10% of the former (resulting in an answer of 9.2ºC)?
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