- #1
jendoley
- 3
- 0
Find the first and second derivative--simplify your answer.
y=x tanx
I solved the first derivative.
y'=(x)(sec^2(x)) +(tanx)(1)
y'=xsec^2(x) +tanx
I don't know about the second derivative though.
y=x tanx
I solved the first derivative.
y'=(x)(sec^2(x)) +(tanx)(1)
y'=xsec^2(x) +tanx
I don't know about the second derivative though.