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Homework Statement
Evaluate
integral csc(x)^4/cot(x)^2 dx
Homework Equations
The Attempt at a Solution
Apparently I'm doing something wrong, what I'm not sure, thanks for any help
My Answer: 2*tan(x) - (sec(x)^2*tan(x))/3 + c
integral csc(x)^4/cot(x)^2 dx
used fact that csc(x) = 1/sin(x)
used fact that cot(x) = 1/tan(x)
used fact that tan(x) = sin(x)/cos(x)
integral sin(x)^2/(sin(x)^4*cos(x)^2) dx
used the fact that x^m/x^n = x^(m-n)
used the fact that x^-m = 1/x^m
integral dx/(sin(x)^2*cos(x)^2)
used the fact that sin(x)^2 + cos(x)^2 = 1
solved for sin(x)^2
sin(x)^2 = 1 - cos(x)^2
integral dx/((1-cos(x)^2)*cos(x)^2)
expanded
integral dx/(cos(x)^2 - cos(x)^4)
broke into two separate integrals
integral dx/cos(x)^2 - integral dx/cos(x)^4
used fact that 1/cos(x) = sec(x)
integral sec(x)^2 dx - integral sec(x)^4 dx
begun evaluating first integral using
integral sec(x)^n = ( sec(x)^(n-2)*tan(x) )/( n-1 ) + ( n-2)/(n-1)*integral sec(x)^(n-2) dx, n =/= 1
(sec(x)^(2-2)*tan(x))/(2-1) - (2-2)/(2-1) integral sec(x)^(2-2) dx - integral sec(x)^4 dx
simplified
tan(x) - integral sec(x)^4 dx
begun evaluating second integral
tan(x) - [(sec(x)^(4-2)*tan(x))/(4-1) - integral sec(x)^2 dx]
simplified
tan(x) - (sec(x)^2*tan(x))/3 + integral sec(x)^2 dx
established already that integral sec(x)^2 dx = tan(x)
2*tan(x) - (sec(x)^2*tan(x))/3 + c
Wolfram Alpha Answer: -2 cot(2 x)+constant
MATLAB Answer: tan(x) - 1/tan(x)
Back of the Book Answer: tan(x) - cot(x) + c
My answer is not equivalent
2*tan(5) - (sec(5)^2*tan(5))/3 is about 7.243183523
tan(5) - 1/tan(5) is about -3.084702091
-2 cot(2*5) is about -3.084702091
tan(5) - cot(5) is about -3.084702091