- #1
Stevecgz
- 68
- 0
In the solutions manual to my calculus text I don't understand how they are simplifying the following:
[tex]x\ln(2x+1)-x+\frac 1 2 \ln(2x+1)+C[/tex]
to...
[tex]\frac 1 2 (2x+1)\ln(2x+1) -x +C[/tex]
If someone could explain to me how they are simplifying this it would be appreciated.
Steve
[tex]x\ln(2x+1)-x+\frac 1 2 \ln(2x+1)+C[/tex]
to...
[tex]\frac 1 2 (2x+1)\ln(2x+1) -x +C[/tex]
If someone could explain to me how they are simplifying this it would be appreciated.
Steve