- #1
Melawrghk
- 145
- 0
Homework Statement
Let g'(x)=-17x16* sin(Ax9) - 9Ax25*cos(Ax9)
g(1)=143/9
Where A is a real number such that tanA=1/sqrt(80), 0<A<pi/2
Find g(0)
The Attempt at a Solution
I was able to get the antiderivative of g'(x), so that:
g(x) = -x17*sin(Ax9)
I got A=6.3794 degrees.
BUT, I don't get g(1)=143/9
What am I doing wrong? Did I assume wrong that the g'(x) was created by the product rule?