Can a Closed Jar Measure the Weight of Flying Bees Inside?

In summary, when weighing a jar with bees flying inside, the mass of the bees will be shown on the scale due to the continuous force they exert downwards while flying. This force is transferred to the air particles, which in turn transfer it to the bottom of the jar. Even if not all of the particles hit the bottom, the increased pressure underneath the bee will support its weight and be transmitted to the scale. This is due to the conservation of momentum in an isolated system.
  • #36
OK... Thanks everyone for the explanation. Now I also think that the weight of flying bees will show on the scale outside.
 
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  • #37
This is easier to comprehend if a person understands how gases exert their weight inside closed containers.

The method for a gas to exert it's weight in a close container is via pressure differential that decreases with height. This net differential in pressure at the top and bottom of the container will generate a net downwards force equal to the weight of the gas inside the closed container. Note that pressure is exerted in all directions, not just downwards; it's the pressure differential versus height that results in a net downwards force.

A somewhat common example is if 6 pounds of air, about 80 cubic feet is put into a scuba tank (at around 3000 psi). The weight of the tank increases by the 6 pounds of air added into it.

If an object is flying or gliding inside a closed container, and there's no net vertical component of acceleration, then the pressure differential will increase so that the net downwards force will equal the sum of the weight of the air and the object.
 
  • #38
Some of the kinetic energy of the air particles moved by bee wing is transferred into the heat and radiated from the jar. Lost energy means lost momentum and hence less net force acting on the bottom of the jar.
Am I wrong?
 
  • #39
zumulko said:
Some of the kinetic energy of the air particles moved by bee wing is transferred into the heat and radiated from the jar. Lost energy means lost momentum and hence less net force acting on the bottom of the jar.
Not all of it gets converted to heat. Some of energy is used up in order to increase the pressure differential so that the net downforce of the air inside the jar exactly equals the sum of the weight of the air and the bee in side the jar.

All too often, how the air inside the jar exerts its own weight on the jar (via a pressure differential, higher at the bottom, lower at the top), isn't taken into account or understood.

One source of confusion, is all the "magical" Bernoulli stuff that seems to imply that lift can occur without acceleration of air downwards to create a reactionary upwards force. In the case of a bee, it's small, the flow is turbulent, and viscosity effects are significant, since the ratio of air affected by viscosity effects versus the size of a bees wings is relatively large. Insect with larger wings, such as a dragon fly, can glide, but bees and bumble bees can't.

Regarding the jet over water, here's a video of a F14 making supersonic passes, the first pass shows the shockwave as a moisture induced cone, the second pass has sound and you can see the shock wave, but no rooster tail on the water, and you'll hear a loud crack instead of a boom, because that's what a supersonic shock wave actually sounds like up close. As the shock wave continue to travel, eventually it transitions into a sound wave which will be a boom we're all much more familiar with.

f14flyby.wmv
 
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  • #40
zumulko said:
Some of the kinetic energy of the air particles moved by bee wing is transferred into the heat and radiated from the jar. Lost energy means lost momentum and hence less net force acting on the bottom of the jar.
Am I wrong?
The lost heat just means the bee has to flap its wings faster than you would expect to stay aloft. It does not mean that the aerodynamic force isn't transferred through the air. Also, remember that in gases, changes in temperature cause changes in pressure.
 
  • #41
this was tested

DaveC426913 said:
This is identical to a classic riddle involving a truck filled with birds crossing a bridge. (I wish I could find an example.) The owner bangs on the side of the truck to get the birds flying, hoping to reduce the weight of the truck. The answer is: no it doesn't work.

If one hasnt lived under a rock in a cave on the other side of town then one would have heard of the show mythbusters. now the show trys to be more scientific than it is but they did this exact expirement and showed that it does register so... Yes
 
  • #42
Let's assume that the bee is moving upward at some angle alpha to the vertical. Flaping is pushing the air particles in the opposite direction of bee movement, giving them momentum p. Then the air particles momentum p_y perpendicular to the bottom of the jar is p*cos(alpha), which is less then p. Does it mean the force acting on the bottom of the jar (and hence the weight) is less than if the bee is hovering?
 
  • #43
lushsector9 said:
If one hasnt lived under a rock in a cave on the other side of town then one would have heard of the show mythbusters. now the show trys to be more scientific than it is but they did this exact expirement and showed that it does register so... Yes

I saw that episode; they busted that myth - the birds did not increase the weight of the container when they were in flight.

http://www.youtube.com/watch?v=DiQq_-_sfAc"

Have you checked the reception in that cave of yours? :rolleyes:
 
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  • #44
We seem to be receiving an influx of people asking this question over and over. Time to lock the thread. It's run its course.
 

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