Can a Generalized Prismatoid Volume be Solved by Axiomatic Means?

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In summary, the conversation discusses a volume problem that can be solved by parametrizing the space and integrating, but can also be solved using axiomatic means. The problem involves constructing a volume on top of a triangle and generalizing it to any shape on the basis. The formula for the volume is Volume = AreaOfBasis x ( hA + hB + hC ) / 3, but it becomes more complex when a fourth point is added. The conversation ends with a suggestion to triangulate the quadrilateral and expressing heights in terms of other parameters to simplify the problem.
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I am trying to solve a volume problem, it is very simple and can be easly solved if the space is parametrized and then integrated.

However, it should also have to be possible to solve the problem by more axiomatic means.

The first version of the problem is: assume that you have a triangle ABC, now you construct a volume on top of this triangle. This volume is build by setting a plane on top of point A at a height of hA, that goes through a point on top of B and C at heights of hB and hC.

Then I want to generalize this problem to have any shape on its basis and assume that the heights will always allow to have a unique plane to define the roof of the volume.

My response, after doing some syntetic geometry on the triangle problem, is:
Volume = AreaOfBasis x ( hA + hB + hC ) / 3
It does make kind of sense to obtain a prism with height being the average of heights.

However, when I add a fourth point (and its height allow us to define a unique plane as a roof) I am not able to deduce the formula.

Any help or hint on how to do it?
 
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If D is the fourth point, triangulate the quadrilateral ABCD. It might simplify the problem if you express hD in terms of hA,hB,hC or all heights in terms of other parameters.
 

FAQ: Can a Generalized Prismatoid Volume be Solved by Axiomatic Means?

What is a prismatoid-ish?

A prismatoid-ish is a three-dimensional geometric shape that has a base with polygonal sides and triangular or trapezoidal lateral faces. It is similar to a prismatoid, but it may not have parallel bases or equal lateral faces.

How do you calculate the volume of a prismatoid-ish?

The volume of a prismatoid-ish can be calculated by multiplying the area of the base by the height of the shape. The formula for the volume of a prismatoid-ish is V = (1/3) * h * A, where h is the height and A is the area of the base.

Can a prismatoid-ish have a volume of zero?

Yes, it is possible for a prismatoid-ish to have a volume of zero. This can happen if the height of the shape is equal to zero, which means the shape is flat and has no depth. In this case, the volume formula would result in a value of zero.

What are some real-life examples of prismatoid-ish shapes?

Some common examples of prismatoid-ish shapes include pyramids with irregular bases, such as the Great Pyramid of Giza, and buildings with trapezoidal or triangular facades, such as the Flatiron Building in New York City. Other examples include tents, roofs, and some types of packaging containers.

How is the volume of a prismatoid-ish different from a prismatoid?

The main difference between the volume of a prismatoid-ish and a prismatoid is that the lateral faces of a prismatoid-ish are not necessarily congruent or parallel to each other. This means that the volume formula for a prismatoid-ish may need to take into account different lateral face areas, while the volume formula for a prismatoid assumes that all lateral faces are congruent and parallel.

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