Can Adiabatic Processes Be Irreversible?

In summary, the conversation discusses the concept of adiabatic processes and the relation PV^y = constant for reversible processes. It also raises a question about the mechanics of a specific gas compression scenario and the applicability of the relation in that case. The conclusion is that the relation is only valid for reversible processes and additional information is needed for a sudden compression scenario.
  • #1
le@rner
5
0
Please help me qualitatively in the following points :
1) If in a system(consider a cylinder) fixed with a piston , if the piston is moved suddenly then how can a process be adiabatic.
2) I understood that the process would be irreversible but, if the process is adiabatic then is the relation PV^y = constant (where y is gamma, P is pressure, V is volume) is true for irreversible process too. (In many books they have written that the relation is true only for reversible processes)

In the following question , I am not getting the real essence of the mechanics of the process. Please explain:

Question:
A gas is enclosed in a cylindrical can fitted with a piston. The walls of the can are adiabatic. The initial pressure, volume and temperature of the gas are 100 kPa, 400 cc (cubic cm) and 300 K respectively. The ratio of the specific heat capacities of the gas is Cp/Cv=1.5 . Find the pressure and temperature of the gas if it is (a)suddenly compressed to 100 cc (cubic cm). (b)slowly compressed to 100 cc (cubic cm).

Here, the answer to both the cases is given same by taking PV^y = constant (where y is gamma)
 
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  • #2
one is constant entropy due to no dissipation in energy. The other isn't so you need to use tables to find the loss due to entropy.

there's no entropy for systems where there's an infinite number of small changes.
 
  • #3
le@rner said:
Please help me qualitatively in the following points :
1) If in a system(consider a cylinder) fixed with a piston , if the piston is moved suddenly then how can a process be adiabatic.
Adiabatic means that no heat enters or leaves the system. If the cylinder is ideally insulated, then no heat will enter or leave the system, irrespective of the nature of the deformation.
2) I understood that the process would be irreversible but, if the process is adiabatic then is the relation PV^y = constant (where y is gamma, P is pressure, V is volume) is true for irreversible process too. (In many books they have written that the relation is true only for reversible processes)
The books you have are correct. The relation is true only for reversible adiabatic processes.
In the following question , I am not getting the real essence of the mechanics of the process. Please explain:

Question:
A gas is enclosed in a cylindrical can fitted with a piston. The walls of the can are adiabatic. The initial pressure, volume and temperature of the gas are 100 kPa, 400 cc (cubic cm) and 300 K respectively. The ratio of the specific heat capacities of the gas is Cp/Cv=1.5 . Find the pressure and temperature of the gas if it is (a)suddenly compressed to 100 cc (cubic cm). (b)slowly compressed to 100 cc (cubic cm).

Here, the answer to both the cases is given same by taking PV^y = constant (where y is gamma)
As I said, the relation is only applicable to reversible adiabatic expansion and compression. This is not the case if the gas is suddenly compressed by a factor of 4. The case of a "sudden" compression cannot be done unless more information is available. An example of the type of additional information that would be required would be specifying that the external force per unit area on the piston is constant, and of appropriate magnitude for the final volume to be 100 cc. This would give a very rapid compression. The rapid compression is going to involve irreversible viscous dissipation of mechanical energy, and cannot be described by the reversible deformation relationship. However, this problem can be solved.

Chet
 

Related to Can Adiabatic Processes Be Irreversible?

1. What is adiabatic thermo problem?

Adiabatic thermo problem refers to a type of thermodynamics problem where there is no heat exchange between the system and its surroundings.

2. What is the first law of thermodynamics?

The first law of thermodynamics states that energy cannot be created or destroyed, only transferred or converted from one form to another.

3. How is adiabatic process different from isothermal process?

In an adiabatic process, there is no heat exchange between the system and its surroundings, while in an isothermal process, the temperature of the system remains constant.

4. What is the equation for adiabatic process?

The equation for adiabatic process is PVγ= constant, where P is pressure, V is volume, and γ is the ratio of specific heat at constant pressure to specific heat at constant volume.

5. How is adiabatic efficiency calculated?

Adiabatic efficiency is calculated by dividing the actual work output of a system by the work output of an ideal adiabatic process with the same input conditions.

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