- #1
Arslan
- 20
- 0
Can Any1 tell me why kienetic energy is equal to both m.v2 and 1/2 m.v2
E=W=F.d
=m.a.d ......=mgh
=m.(v/t).d
=m.(d/t^2).d
=m.d^2/t^2
=m.v^2
So hence proved K.E= m.v^2
But 2.a.s=Vf2-Vi2 Newton equatio of motion
2.F/m.s=V2......if initial velocity is zero
F.s=1/2 mv2
W=E=1/2 mv2
So hence proved K.E=1/2 m.v^2
E=W=F.d
=m.a.d ......=mgh
=m.(v/t).d
=m.(d/t^2).d
=m.d^2/t^2
=m.v^2
So hence proved K.E= m.v^2
But 2.a.s=Vf2-Vi2 Newton equatio of motion
2.F/m.s=V2......if initial velocity is zero
F.s=1/2 mv2
W=E=1/2 mv2
So hence proved K.E=1/2 m.v^2