- #1
danielatha4
- 113
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Car A is dropped at 4000 ft where directly below is an x on the road. At the instant Car A is dropped Car B is exactly 4000 ft from the x driving down the road at a constant velocity of 142 mph. Does Car B make it past the x in time to avoid disaster?
It's such a simple kinematics problem that it's beautiful but unfortunately you have to take into consideration wind resistance Can anyone show an accurate application of wind resistance in this problem? From my understanding the mass of the car is 1600 kg and it dropped staying flat landing virtually on all 4 tires at the same time.
For the heck of it I'll do the kinematics neglecting wind resistance:
time Car B takes to get to the x
x=vt
1219.2m = 63.5 m/s * t
t = 19.2 seconds
Does Car A hit the road is less time or more time than 19.2 seconds?
x=vot+1/2at2
x = 0 + 4.9 * 19.22
x = 1806.336m
therefore, less time
time it takes Car A to hit the road
x = 1/2at2
1219.2m = 4.9 * t2
t = 15.77 seconds
Seems like air resistance and terminal velocity make all the difference here
It's such a simple kinematics problem that it's beautiful but unfortunately you have to take into consideration wind resistance Can anyone show an accurate application of wind resistance in this problem? From my understanding the mass of the car is 1600 kg and it dropped staying flat landing virtually on all 4 tires at the same time.
For the heck of it I'll do the kinematics neglecting wind resistance:
time Car B takes to get to the x
x=vt
1219.2m = 63.5 m/s * t
t = 19.2 seconds
Does Car A hit the road is less time or more time than 19.2 seconds?
x=vot+1/2at2
x = 0 + 4.9 * 19.22
x = 1806.336m
therefore, less time
time it takes Car A to hit the road
x = 1/2at2
1219.2m = 4.9 * t2
t = 15.77 seconds
Seems like air resistance and terminal velocity make all the difference here