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Olinguito said:Another hint:
Use the well-known result $\displaystyle\lim_{x\to0}\frac{\sin x}x=1$.
The concept of "Proof Continuous at x = 0" refers to a mathematical property of a function where the value of the function at x = 0 is equal to the limit of the function as x approaches 0 from both the left and right sides.
To prove continuity at x = 0, you must show that the left and right limits of the function at x = 0 are equal and that the function is defined at x = 0. This can be done using various methods such as the epsilon-delta definition, the intermediate value theorem, or the continuity of composite functions.
Continuity at x = 0 is important because it allows us to understand and analyze the behavior of a function at a specific point. It also helps us identify any potential discontinuities in a function, which can have significant implications in various fields of mathematics and science.
If a function is not continuous at x = 0, it means that the left and right limits of the function at x = 0 are not equal. This can result in a discontinuity at x = 0, which can lead to unexpected or undefined behavior of the function at that point.
Yes, it is possible for a function to be continuous at x = 0 but not at other points. This means that the function satisfies the definition of continuity at x = 0, but it may have discontinuities at other points. This highlights the importance of considering continuity at specific points rather than assuming continuity for the entire function.