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LAByrinthAC
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Hey guys can we derive the formula of Electric Field Intensity around a uniformly charged ring if yes please share the derivation thanks
Gauss Law on a charged ring is a mathematical law that relates the electric field around a charged ring to the amount of charge enclosed by the ring. It is based on the principle of flux, which states that the total electric flux through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space.
Gauss Law on a charged ring and Gauss Law on a charged sphere are both applications of the same principle of flux. However, they differ in terms of the shape and symmetry of the charged object. Gauss Law on a charged ring applies to a ring with circular symmetry, while Gauss Law on a charged sphere applies to a sphere with radial symmetry.
The formula for Gauss Law on a charged ring is E = Q/(2πε₀r), where E is the electric field, Q is the charge enclosed by the ring, ε₀ is the permittivity of free space, and r is the distance from the center of the ring to the point where the electric field is being measured.
Yes, Gauss Law on a charged ring can be applied to non-uniformly charged rings. However, in this case, the calculation of the electric field becomes more complicated as it will vary at different points along the ring. It is easier to apply Gauss Law on a charged ring to a uniformly charged ring.
Gauss Law on a charged ring has many practical applications, including the design of electric motors and generators, as well as the calculation of the electric field around charged particle accelerators. It is also used in the study of magnetohydrodynamics, which is the science of the interaction between magnetic fields and electrically conducting fluids.