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sodoyle
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- TL;DR Summary
- I would like to know if I can connect buck converters in series. I am looking at the LT1170HV specifically
I have two capacitors in series across my bus. I have a some series resistors across the capacitors for voltage balancing. I would like to power some low voltage low voltage components tapping off of the voltage divider using that as the voltage supply.
The bus voltage will be approximately 2 kV. The DC/DC converter I'm planning to use is the LT1170HV which has a maximum input voltage of 60 V. I would like to operate this near 20 V and need a load current of approximately 20 mA at 5 V. The application note for this chip recommended a minimum load of 100 mA so I guess I'll have to add a dummy load on the low voltage side to draw more current.
To find the input current to the converter, I used D=Vo/Vin and Iin=D*Io. With Vin=20 and Vo=5, I get D=0.25 and Iin= 25 mA.
Since this converter will be in parallel with a resistor from the voltage divider, I'll assume the input input impedance of the converter is equal to the resistance of the parallel resistor used as its source. In that case, the current through the voltage divider must be 2*Iin or 50 mA.
To get current of 50 mA through the voltage divider, Req=2000/(.05)=40 kOhm
Using Zin = Vin/Iin, and Iin= 25 mA, I find Zin=800 Ohm.
The voltage divider would then look like some number of resistors totaling approximately 39.2 kOhm with a 1.6 kOhm resistor at the bottom. With the converter connected and drawing power, the equivalent resistance of the would then be approximately 40 kOhm (in the ideal world) i think right?
I'm sure there are a lot of problems with this approach so please berate this approach and help me find a better solution. The first problem that I see is the resistors would be dissipating roughly 100 W. Actually, that piece alone stops me from going further with this. Is my math and approach correct from all of the steps above?
I was thinking maybe I could use several converters in series so I could tap off a higher voltage requiring a lower input current. I would have to series several bucks to get down to 5 V because the converters that do like 700/5 V conversion are WAY outside of my price range.
Any recommendations are greatly appreciated.
The bus voltage will be approximately 2 kV. The DC/DC converter I'm planning to use is the LT1170HV which has a maximum input voltage of 60 V. I would like to operate this near 20 V and need a load current of approximately 20 mA at 5 V. The application note for this chip recommended a minimum load of 100 mA so I guess I'll have to add a dummy load on the low voltage side to draw more current.
To find the input current to the converter, I used D=Vo/Vin and Iin=D*Io. With Vin=20 and Vo=5, I get D=0.25 and Iin= 25 mA.
Since this converter will be in parallel with a resistor from the voltage divider, I'll assume the input input impedance of the converter is equal to the resistance of the parallel resistor used as its source. In that case, the current through the voltage divider must be 2*Iin or 50 mA.
To get current of 50 mA through the voltage divider, Req=2000/(.05)=40 kOhm
Using Zin = Vin/Iin, and Iin= 25 mA, I find Zin=800 Ohm.
The voltage divider would then look like some number of resistors totaling approximately 39.2 kOhm with a 1.6 kOhm resistor at the bottom. With the converter connected and drawing power, the equivalent resistance of the would then be approximately 40 kOhm (in the ideal world) i think right?
I'm sure there are a lot of problems with this approach so please berate this approach and help me find a better solution. The first problem that I see is the resistors would be dissipating roughly 100 W. Actually, that piece alone stops me from going further with this. Is my math and approach correct from all of the steps above?
I was thinking maybe I could use several converters in series so I could tap off a higher voltage requiring a lower input current. I would have to series several bucks to get down to 5 V because the converters that do like 700/5 V conversion are WAY outside of my price range.
Any recommendations are greatly appreciated.
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