Can Induction Prove the Equality of Cubic and Square Sums?

In summary, the conversation is about proving the equation \sum\limits_{i=0}^n i^3 = (\sum\limits_{i=0}^N i)^2 by induction. The individual has attempted to solve it by using N=1 and by assuming it is valid up to a limit k, but has run into a problem where the left hand side has a k^3 term while the right hand side has a k^2 term. They have been advised to look for a pattern using the expression for the sum of i from 1 to n, which is n*(n+1)/2, and to square it to possibly find a k^3 term.
  • #1
Trentonx
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Homework Statement



Prove by induction [tex]\sum\limits_{i=0}^n i^3 [/tex] [tex]= (\sum\limits_{i=0}^N i)^2 [/tex]

Homework Equations


The Attempt at a Solution



So I used [tex] N=1 [/tex] and found that indeed, [tex] 1^3 = (1)^2 [/tex]

Then I assumed it was valid up to some limit k, and tried to find it for k+1
[tex] (1^3+2^3+...+k^3+(k+1)^3)=(1+2+...+k+k+1)^2 [/tex]
[tex] (9+...+2k^3+3k^2+1)=(4+...+2k)^2 [/tex]
Right here I can see a problem, since the RHS will have a [tex] k^2 [/tex] term, and the LHS will have [tex] k^3 [/tex]. Where did I go wrong? Are they supposed to be equal?
Thanks for any help.
 
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  • #2
Do you know the expression Sum of i 1 to n is n*(n+1)/2 ? There's a pattern there. When you sqaure it, maybe you will find a k^3
 

FAQ: Can Induction Prove the Equality of Cubic and Square Sums?

What is a series proof by induction?

A series proof by induction is a method of proving a statement or formula for all natural numbers by using mathematical induction. It involves showing that the statement holds for the first natural number, and then showing that if it holds for any given natural number, it also holds for the next natural number. This process is repeated until it can be shown that the statement holds for all natural numbers.

What is the difference between mathematical and strong induction?

Mathematical induction is a method of proving a statement for all natural numbers by showing that it holds for the first natural number and then assuming that it holds for an arbitrary natural number, and proving that it holds for the next natural number. Strong induction, on the other hand, involves assuming that the statement holds for all natural numbers up to a given natural number, and then proving that it holds for the next natural number. Strong induction is a more powerful technique and can be used to prove more complex statements.

How do you know when to use a series proof by induction?

Series proof by induction is typically used when the statement or formula to be proven involves natural numbers or integers. It is also useful when the statement involves a recursive definition, where the value of a term depends on the values of previous terms. Additionally, if the statement can be proven for the first few natural numbers and then for an arbitrary natural number, it is a good indication that a series proof by induction may be applicable.

What are the steps for a series proof by induction?

The steps for a series proof by induction are as follows:

  1. Prove that the statement holds for the first natural number (often 0 or 1).
  2. Assume that the statement holds for an arbitrary natural number, usually denoted as k.
  3. Using this assumption, prove that the statement also holds for the next natural number, k+1.
  4. Conclude that the statement holds for all natural numbers by mathematical induction.

Can a series proof by induction be used for real numbers?

No, a series proof by induction can only be used for natural numbers. This is because the principle of mathematical induction relies on the fact that the natural numbers have a well-defined order and can be counted in a consecutive manner. Real numbers do not have this property and thus, series proof by induction cannot be applied to them.

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