- #1
MupptMath
- 4
- 0
Hi,
I'm stuck on the following proof:
\(\displaystyle \log[3] = \frac 1{729} \sum_{k=0}^\infty \frac 1{729^k} \left[\frac{729}{6k+1}+\frac{81}{6k+2}+\frac{81}{6k+3}+\frac 9{6k+4}+\frac 9{6k+5}+\frac 1{6k+6}\right]\)
Manipulating and converting summands to integrals of the form $x^{-(6k+n)}$ over {x,0,3} seems to provide a nice reduction but does not converge in that interval and am uncertain how to proceed. Manipulating indices and summands to reduce to certain series doesn't quite work. Seems so close, but so far.
Thanks.
I'm stuck on the following proof:
\(\displaystyle \log[3] = \frac 1{729} \sum_{k=0}^\infty \frac 1{729^k} \left[\frac{729}{6k+1}+\frac{81}{6k+2}+\frac{81}{6k+3}+\frac 9{6k+4}+\frac 9{6k+5}+\frac 1{6k+6}\right]\)
Manipulating and converting summands to integrals of the form $x^{-(6k+n)}$ over {x,0,3} seems to provide a nice reduction but does not converge in that interval and am uncertain how to proceed. Manipulating indices and summands to reduce to certain series doesn't quite work. Seems so close, but so far.
Thanks.
Last edited by a moderator: