- #36
MeJennifer
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You are missing the point, the traveling clock will not measure the roundtrip time of light at all it will simply desynchronize from the Earth's clock due to its speed differential when it traveled and hence all it will "measure" is the time difference between the Earth's clock when it will come back to Earth.JesseM said:OK, so imagine a clock that starts at Earth at the moment the light is emitted, accelerates to some high fraction of lightspeed, then later turns around and makes it back to Earth in time for the light's return. Here we have used a single clock to measure both departure and return too, so isn't this a "roundtrip" time? If you restrict roundtrip time to inertial clocks, what physical justification do you have for saying roundtrip time measured by inertial clocks is somehow more "real" than roundtrip time measured by non-inertial clocks?
It is not about the clock but about the time it takes light to go from A to B. For instance if Earth or Sirius B were to accelerate the roundtrip time of light, due to special relativity, would obviously change. But obviously the time it takes light to go from A to B does not depend on Jimmy going on a trip with a clock that is going to be desynchronized with a clock on Earth.
Edited to add:
We actually do not have to restrict ourselves to intertial clocks. Suppose both Earth and Sirius B are accelerating then we still can record a roundtrip time and determine how long it takes light to go from Earth to Sirius B and back, however we would have to realize that the roundtrip time may not remain constant over time if the accelerations are variable, a situation a bit like distances in non-stationary spacetimes in GR.
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