Can s oribtal electrons only drop to other s orbitals?

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Electrons in s orbitals, characterized by a momentum quantum number of l = 0, can only transition to other s orbitals if they drop in energy. However, when an s state electron emits a photon, it typically transitions to a p orbital (l = 1) due to the requirement of a change in angular momentum (Δl = 1). This is because dipole transitions are only allowed between states of different symmetry, specifically between odd and even states. As a result, direct transitions from s to s orbitals are not permitted. The discussion highlights the constraints of quantum mechanics on electron transitions and the role of symmetry in these processes.
friendbobbiny
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Just a thought:

The momentum quantum number given for s states is l = 0. If an S state electron dropped in energy, and emitted a photon with l = 1, what would take place?


Am I correct that the electron could only drop to a lower l = 0 (an S state) orbital?
 
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Dipole transitions from s are only allowed to p orbitals.
 
Why can't a drop to s take place? I infer that a drop to p(l = 1) can take place because \Delta l = 1.
 
The dipole operator is odd, so it only gives overlap between states with odd and even symmetry.
 

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