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keishuu
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Homework Statement
A manometer is attached to a pipe on end and open on the other. The manometer fluid is n-heptane while the process fluid is nitrogen gas. If the height difference between the two is 680 mm what is the pressure of the fluid in the pipe?
Homework Equations
P1-P2 = density of manometer fluid*g*h <---since process fluid is a gas
The Attempt at a Solution
I figured that you would be solving for P1 and so I did
P1-1 atm=9.8N/kg x 684 kg/m^3 (this is the density of n-heptane) x .680 m x 1 atm/1.01325x 10^5 = .045 atm
P1=1 atm+.045 atm = 1.045 atm
I'd really appreciate if someone could help me on this. Thanks!