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nickb145
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Alright, I know how to find the integral of a regular function, But an inverse, is throwing me off
Can someone explain why 1/Sqrt(7t)dt is 2sqrt(t/7)
I'm probably missing something, but why does the variable end up as a numerator?
I know the inverse is 1/(r+1)x^(r+1)
So I work it out as
1/(-.5+1) which goes out to 2
then the rest
(7t)^-1/2+1
(7t)^1/2
(what am I missing here)
=2sqrt(t/7)+C
Can someone explain why 1/Sqrt(7t)dt is 2sqrt(t/7)
I'm probably missing something, but why does the variable end up as a numerator?
I know the inverse is 1/(r+1)x^(r+1)
So I work it out as
1/(-.5+1) which goes out to 2
then the rest
(7t)^-1/2+1
(7t)^1/2
(what am I missing here)
=2sqrt(t/7)+C