- #1
Jonas E
- 15
- 0
Homework Statement
I have the circuit in the picture below, and using KCL and KVL I found that the voltage over the 80k resistor is 0. However, I don't understand why this is correct. Can someone explain why there is no current through it?
Homework Equations
None
The Attempt at a Solution
I used the node voltage method to get 25ib + 1/(16k)-i0 = 0. After that I used KVL through the 80k resistor, 16k resistor and 1V source, which gave me 80k * ib - 1 + 1 = 0. So ib = 0.