- #1
SansaStark
- 15
- 0
Okay, it's not easy for me but probably for you ;)
Hello first of all!
I have two questions:
1. Why is there a minus before the expression in the red circle?
2. How did the x((n-1)-1) in the last line come to be?More precise: I understand the first parts. It's the random walk and x signifies the position of a particle after n steps. Then (n-1) ist the position of teh particle having moved to either the left or right side (this is 1-dimensional) and the δ is the distance the particle has travelled. But why is there a minus in the third line before the second 1/N? I mean how do I imagine that visually? I kind of have a notion but I can't really grasp it. And then in the last line why is the [x(n-1)] the same as [x((n-1)-1)]? Huh? oO
Okay, here is the equation:
Thanks a lot already!
Vera
Hello first of all!
I have two questions:
1. Why is there a minus before the expression in the red circle?
2. How did the x((n-1)-1) in the last line come to be?More precise: I understand the first parts. It's the random walk and x signifies the position of a particle after n steps. Then (n-1) ist the position of teh particle having moved to either the left or right side (this is 1-dimensional) and the δ is the distance the particle has travelled. But why is there a minus in the third line before the second 1/N? I mean how do I imagine that visually? I kind of have a notion but I can't really grasp it. And then in the last line why is the [x(n-1)] the same as [x((n-1)-1)]? Huh? oO
Okay, here is the equation:
Thanks a lot already!
Vera