- #1
Tracee
- 4
- 0
Q = C (90pF) x V (25 volts)
90 x 10e-12
x 25 = 2.25 x 10e-9 Coulombs (2.25nC)
I get this equation for charge but my maths is letting me down.
How do I get from 90pF (90 to power of -12) x 25 = 2.25 x 10 to power of -9
I don't know the working out with negative exponents. I may have to duplicate in a test so I need a simple way.
This subject is doing my head in - the chemistry, physics and maths does not come naturally...grrr
90 x 10e-12
x 25 = 2.25 x 10e-9 Coulombs (2.25nC)
I get this equation for charge but my maths is letting me down.
How do I get from 90pF (90 to power of -12) x 25 = 2.25 x 10 to power of -9
I don't know the working out with negative exponents. I may have to duplicate in a test so I need a simple way.
This subject is doing my head in - the chemistry, physics and maths does not come naturally...grrr