- #1
rabbed
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- TL;DR Summary
- Exact Boltzmann distribution
Hi
With the exact Boltzmann distribution, ni = InverseDigamma(-α-β*εi)-1:
https://studyres.com/doc/269738/revision-of-boltzmann-statistics-for-a-finite-number-of-p...
Shouldn't I be able to get (n0, n1, n2, n3, n4, n5, n6, n7) = (6, 3, 2, 0, 0, 0, 0, 0) for some α and β, if N=11, E=7 and Δε=1?
It doesn't seem possible.
With the exact Boltzmann distribution, ni = InverseDigamma(-α-β*εi)-1:
https://studyres.com/doc/269738/revision-of-boltzmann-statistics-for-a-finite-number-of-p...
Shouldn't I be able to get (n0, n1, n2, n3, n4, n5, n6, n7) = (6, 3, 2, 0, 0, 0, 0, 0) for some α and β, if N=11, E=7 and Δε=1?
It doesn't seem possible.