- #1
reza
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- 0
f(x) =2x + ln x
f^-1(x)=?
i do
f(x)=2x +lnx=ln (e^2x) + ln x = ln [(e^2x)x]
=>e^f(x)=e^2x(x)=>
can eny body solve this equation
f^-1(x)=?
i do
f(x)=2x +lnx=ln (e^2x) + ln x = ln [(e^2x)x]
=>e^f(x)=e^2x(x)=>
can eny body solve this equation