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solakis1
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Can the No :$4\sqrt{4-2\sqrt {3}}+\sqrt{97-56\sqrt 3}$ be an iteger ,if yes prove it if no then prove it again
The equation in question is No $4\sqrt{4-2\sqrt {3}}+\sqrt{97-56\sqrt 3}$
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Yes, the equation is solvable since it is a mathematical expression that follows the rules of algebra.
The numbers and symbols in the equation represent mathematical operations and values. The square root symbol (√) indicates the square root of a number, and the caret symbol (^) is used to represent exponents. The numbers in the equation are constants, meaning they have a fixed value.
Yes, it is possible for the result of the equation to be an integer. However, it is not guaranteed since the equation contains square roots and exponents, which can result in irrational numbers.
The equation can be solved by simplifying the expression and then evaluating it. If the result is a whole number, then it is an integer. If the result is a decimal or fraction, then it is not an integer.