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judas_priest
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Homework Statement
Two cyclists are in a race. One cyclist knows that he is slower, so he cheats: he removes the faster cyclist’s bike chain. The cheater starts from rest immediately with acceleration 2.5 m/s2. The faster cyclist has to take 3 seconds to replace her bike chain. She then follows (also from rest) with acceleration 3.0 m/s2. Assume that both cyclists accelerate smoothly and that they do not reach their maximum speeds during this race.
What is the maximum length that the race can be (in meters) in order for the slower cyclist to win?
The attempt at a solution
I used [itex] x = 1/2(at^2)[/itex] and plugged in the values of the cheater cyclist into the equation.( t = 3, a = 2.5)
Found x (came out as 11.25), plugged the same value of x into the equation with acceleration of the faster cyclist. This gave me the time it would take for the faster cyclist to reach that same position the cheater cyclist reached in 3 seconds. got t = 2.7. Plugged in t = 3+2.7 into the equation to get the position of the cheater cyclist at the time when the faster cyclist reached the position x = 11.25. Kept doing this, but it's taking me nowhere. Is there a simpler way to solve this problem?