- #1
AakashPandita
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Can we write icap-jcap=pi/2 ? why or why not?
icap-jcap = pi/2; // is an invalid construct
// as you can have an expression icap-jcap
// on the left of an assignment
if ((icap-jcap)==(pi/2)) { System.out.println("icap-jcap == pi/2 is TRUE");
AakashPandita said:UltrafastPED is right.
I was trying to prove that radial acceleration of a body moving in circle is v^2/r.
For uniform speed i came up with this 2v^2(icap-jcap)/rpi as radial acceleration
If icap-jcap=pi/2, acc=v^2/r
Also i do not understand computer programs.
AakashPandita said:2v^2(icap-jcap) / rπ
is the average acc. for 90 degree of circular motion.
is there a way i could obtain instantaneous acceleration from this expression?
how?
also how do i write it in latex?
AakashPandita said:yes i know that method. is there a proof ...like maybe we could find average acceleration for time tending to zero...?
AakashPandita said:I get change in velocity:
[tex]\frac{( sinθ \hat{i} + ( cosθ - 1 ) \hat{j} ) v^2}{θr}[/tex]
where θ is change in velocity and in radian and less than pi/2, speed is constant and body starts moving from
[tex]v\hat{j}[/tex]
AakashPandita said:I get change in velocity:
[tex]\frac{( sinθ \hat{i} + ( cosθ - 1 ) \hat{j} ) v^2}{θr}[/tex]
where θ is change in velocity and in radian and less than pi/2, speed is constant and body starts moving from
[tex]v\hat{j}[/tex]
I'm sorry. I was thinking of it going counter clockwise starting at (r,0). The way you have it drawn is consistent with your equation. And, as your result indicates, it should be a +i unit vector (which points at the origin).AakashPandita said:clearly sinθ is positive?
No, we cannot write icap-jcap=pi/2 because the equation is not mathematically valid. The left side of the equation represents a vector, while the right side represents a numerical value. In order for the equation to make sense, both sides must represent the same type of mathematical object.
As mentioned before, icap-jcap is a vector, while pi/2 is a numerical value. These two objects cannot be equal because they are not the same type of mathematical object. Therefore, it is not possible to write icap-jcap=pi/2.
Yes, the equation can be rewritten as icap-jcap = pi/2 * jcap, where jcap represents a unit vector in the y-direction. This equation is now valid because both sides represent vectors.
No, we cannot solve for icap-jcap in this equation because there is no variable or unknown value to solve for. The equation simply states that two different types of mathematical objects are equal, which is not mathematically valid.
This equation has no significant meaning in mathematics or science. It is not a valid equation and cannot be used to represent any physical or mathematical concept. Therefore, it does not have any significance.