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Albeaver
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Can you check this? -- Charges and Forces...
A +3-mC charge and a -4-mC charge are fixed in position and separated by 5 meters.
A)Where could a +7-mC charge be placed so that the net force on it is zero?
B)Where could a -7-mC charge be placed so that the net force on it is zero?
I came up with this diagram:
|---------------5m------------------|
*----------------*------------------*
q[1] q[2] q[3]
|-------r[1]------|----------r[2]----|
F[1]=K(|q[1]*q[2]|)/r[1]^2
F[2]=K(|q[2]*q[3]|)/r[2]^2
r[1]+r[2]=5
k=8.99*10^9
|q[1]|=4
|q[3]|=3
|q[2]|=7
F[1]=F[2]<---Because they are equal
K(q[1]*q[2])/r[1]^2=K(q[3]*q[2])/(5-r[1])^2<---We get (5-r[1])=r[2] from r[1]+r[2]=5 solved for r[2])
Then after we solve for r[1] we get this:
r[1]=5*√(q[3])*(√(q[3])-√(q[1]))/(q[3]-q[1])
So that means that both the +7-mC charge and the -7-mC charge are in the same position. The number I got was r[1]=2.32m and r[2]=2.68m. Did I set this up, and execute this correctly?
Thank you very much for your time.
Homework Statement
A +3-mC charge and a -4-mC charge are fixed in position and separated by 5 meters.
A)Where could a +7-mC charge be placed so that the net force on it is zero?
B)Where could a -7-mC charge be placed so that the net force on it is zero?
I came up with this diagram:
|---------------5m------------------|
*----------------*------------------*
q[1] q[2] q[3]
|-------r[1]------|----------r[2]----|
Homework Equations
F[1]=K(|q[1]*q[2]|)/r[1]^2
F[2]=K(|q[2]*q[3]|)/r[2]^2
r[1]+r[2]=5
k=8.99*10^9
|q[1]|=4
|q[3]|=3
|q[2]|=7
The Attempt at a Solution
F[1]=F[2]<---Because they are equal
K(q[1]*q[2])/r[1]^2=K(q[3]*q[2])/(5-r[1])^2<---We get (5-r[1])=r[2] from r[1]+r[2]=5 solved for r[2])
Then after we solve for r[1] we get this:
r[1]=5*√(q[3])*(√(q[3])-√(q[1]))/(q[3]-q[1])
So that means that both the +7-mC charge and the -7-mC charge are in the same position. The number I got was r[1]=2.32m and r[2]=2.68m. Did I set this up, and execute this correctly?
Thank you very much for your time.