sony
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how to go from: [(1+n)^n]/n to: (1+1/n)^n ?
Sorry, that's what I meant. Can you show me how you get to the right hand expression?BerryBoy said:http://www.berrys.plus.com/hh3.gif
You can check if you can get to a another equation by substuting values into 'n'.
Regards,
Sam
matt grime said:you realize you're asking for someone to explain why (1+2)/2 = 1/2 +2/2, or more generally that (a+b)/c = (a/c)+(b/c), which is something you learn in primary/elementary school, right?