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DrLiangMath
- 22
- 3
MathTutoringByDrLiang said:The key idea is to view $x+\frac{1}{x}$ as a whole. There are four real solutions: $x=\frac{3±\sqrt{5}}{2}$, $x=\frac{-3±\sqrt{5}}{2}$ (and two complex solutions: $x=±i$). Here is the explanation:
Thank you very much for your feedback!topsquark said:Nice idea!
Or you could just multiply both sides by $x^3$ and sub in $y = x^2$. The resulting cubic equation for y is easy to solve using the rational root theorem.
-Dan
To solve a double cubic algebraic equation, you can use the cubic formula or factorization. The cubic formula involves plugging in the coefficients of the equation into a formula, while factorization involves finding common factors and using the zero product property.
The cubic formula is a mathematical formula used to solve cubic equations. It is given by x = (-b ± √(b^2 - 4ac - 3b^3) / 2a, where a, b, and c are the coefficients of the cubic equation.
Yes, all double cubic algebraic equations can be solved using either the cubic formula or factorization. However, the solutions may involve complex numbers.
Yes, there are two special cases when solving a double cubic algebraic equation: when all three roots are real and distinct, and when one root is real and the other two are complex conjugates. In these cases, the cubic formula can be simplified.
Yes, a computer can solve a double cubic algebraic equation by using numerical methods such as the Newton-Raphson method or the bisection method. These methods involve approximating the roots of the equation using iterative calculations.