Can You Solve This Equation Using Newton-Raphson Method?

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In summary, the conversation discusses a problem where an equation needs to be solved to a precision of thousandths. The solution, as mentioned, is approximately 0.199. Various methods are suggested, including Newton's Method and bisection, and there is a discussion about the correct way to spell "Newton-Raphson."
  • #1
dlp211
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Homework Statement

3b^(2/3) - 2b = 10/16

Find solution to a precision of thousanths



The attempt at a solution

I know the answer is ~ .199, I do not however know how to actually solve the above equation. If anyone can help, I'd appreciate it, it's been over 10 years since I took an algebra class.
 
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  • #2
dlp211 said:
Homework Statement

3b^(2/3) - 2b = 10/16

Find solution to a precision of thousandths

The attempt at a solution

I know the answer is ~ .199, I do not however know how to actually solve the above equation. If anyone can help, I'd appreciate it, it's been over 10 years since I took an algebra class.
Reduce 10/16 → 5/8.

Isolate the 3b2/3 by adding 2b to both sides.

Cube both sides.

The result is a cubic equation. This particular cubic equation does not have any rational solutions.

Use the bisection method, starting with a very small interval near 0.2. There is the solution near 0.2, as you said, but there's another nearby; between -0.1 and 0 .

There is a third solution that's between 2 and 3.
 
  • #3
dlp211 said:
Homework Statement

3b^(2/3) - 2b = 10/16

Find solution to a precision of thousanths



The attempt at a solution

I know the answer is ~ .199, I do not however know how to actually solve the above equation. If anyone can help, I'd appreciate it, it's been over 10 years since I took an algebra class.

I believe Newton-Rhapsody iterative solving method might help you to find the roots if they are real ofcourse:

http://en.wikipedia.org/wiki/Newton's_method
 
  • #4
Thanks guys,

This was the end of a much larger problem and it now makes sense that I need to use the Newton's Method(this is was the end of a Calc II) problem.

It's been a long time for some algebra concepts for me so I appreciate all the help.

Dave
 
  • #5
dlp211 said:
Thanks guys,

This was the end of a much larger problem and it now makes sense that I need to use the Newton's Method(this is was the end of a Calc II) problem.

It's been a long time for some algebra concepts for me so I appreciate all the help.

Dave
This is the pre-calculus section, so I suggested bisection.

Make sure your initial guess is close enough to the root you want to find. Newton's Method may find a different root if you don't start close enough to the one you're interested in.
 
  • #7
But "Rhapsody" sounds so much better!
 
  • #8
Mark44 said:
There's Newton-Raphson, which is probably what you were thinking of.

HallsofIvy said:
But "Rhapsody" sounds so much better!

Well, there's that.
 

FAQ: Can You Solve This Equation Using Newton-Raphson Method?

What is the meaning of the term "solve" in this equation?

The term "solve" in this equation means to find the value of the variable, b, that makes the equation true.

How do you solve this equation?

To solve this equation, you can use algebraic techniques such as isolating the variable on one side of the equation, combining like terms, and using the properties of exponents.

Can this equation be solved without using exponents?

Yes, this equation can be solved without using exponents by rewriting the equation as 3b^(2/3) - 2b = 10/16 = 5/8 and then solving for b using traditional algebraic techniques.

What are the possible solutions for this equation?

The possible solutions for this equation are all real numbers except for b = 0, as that would result in an undefined term (0^(2/3)).

Can this equation be solved using a graphing calculator?

Yes, this equation can be solved using a graphing calculator by graphing the left side of the equation and the right side of the equation and finding the point(s) of intersection, which would represent the solution(s) for b.

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