- #1
nik2011
- 12
- 0
Hello guys!
This is not quite a homework, but anyway.
I'm trying to figure out some details about the circuit below.
The circuit contains two voltage sources. V1 is 5V 100Hz AC source, V2 is 15V DC source.
I know I can analyze this circuit simply treating it as if there are two currents. One is direct current, the other one is alternating current. But this is only a convenient way to analyze a circuit.
And I'm trying to imagine what's happening on a bit "lower" level.
So when AC source's voltage is increasing the current is increasing too and so more electrons are flowing through the wire. And bigger part of these electrons flow through the capacitor.
When AC source is decreasing the current though the V1 and V2 doesn't change its direction but only decreases its value because the effective voltage across the circuit decreases but still is positive (E. g. 15V - 5V = 10V). But the current through the circuit branch with the capacitor changes its direction to the opposite.
What I don't understand is how the voltage drop between the point A and the ground is formed.
1. Is it like this: V1 voltage decreases -> the current decreases -> the capacitor "sees" that the current decreased and starts to discharge?
If so, how exactly can the capacitor "see" that the current changed?
2. Or it is like the following: V1 voltage decreases -> the current decreases -> the voltage drop across R2 decreases -> because the voltage drop decreased the capacitor starts to discharge?
But in this case, the voltage drop across R2 is the same as the voltage drop between the point A and the ground. And the voltage drop between A and the ground depends on the currents through R2 and the capacitor, and the current through the capacitor depends on the voltage drop between A and the ground...
If the question is not clear enough I would be glad to clarify.
Thank you!
This is not quite a homework, but anyway.
Homework Statement
I'm trying to figure out some details about the circuit below.
The circuit contains two voltage sources. V1 is 5V 100Hz AC source, V2 is 15V DC source.
I know I can analyze this circuit simply treating it as if there are two currents. One is direct current, the other one is alternating current. But this is only a convenient way to analyze a circuit.
And I'm trying to imagine what's happening on a bit "lower" level.
The Attempt at a Solution
So when AC source's voltage is increasing the current is increasing too and so more electrons are flowing through the wire. And bigger part of these electrons flow through the capacitor.
When AC source is decreasing the current though the V1 and V2 doesn't change its direction but only decreases its value because the effective voltage across the circuit decreases but still is positive (E. g. 15V - 5V = 10V). But the current through the circuit branch with the capacitor changes its direction to the opposite.
What I don't understand is how the voltage drop between the point A and the ground is formed.
1. Is it like this: V1 voltage decreases -> the current decreases -> the capacitor "sees" that the current decreased and starts to discharge?
If so, how exactly can the capacitor "see" that the current changed?
2. Or it is like the following: V1 voltage decreases -> the current decreases -> the voltage drop across R2 decreases -> because the voltage drop decreased the capacitor starts to discharge?
But in this case, the voltage drop across R2 is the same as the voltage drop between the point A and the ground. And the voltage drop between A and the ground depends on the currents through R2 and the capacitor, and the current through the capacitor depends on the voltage drop between A and the ground...
If the question is not clear enough I would be glad to clarify.
Thank you!