Center of mass of a ring of variable density

In summary, to find the center of mass (COM) for a ring of variable density, described by a continuous mathematical equation, you would need to integrate in x and y coordinates and use the formula R = \int p(r) * r dV / \int p(r) dV, where p(r) is the density function and dV is the volume element. This can also be restated as a "barycenter" problem, but finding the COM for m2 is not straightforward.
  • #1
redtree
331
14
How would I find the center of mass (COM) for a ring of variable density, where the variation in density can be described by a continuous mathematical equation.

The density at each location along the ring is described by a function (d) whose independent variables are radius (r) and angle ([tex]\theta[/tex]), i.e., polar coordinates.

The value of d at each r and [tex]\theta[/tex] is the sum of two functions (d1 and d2) where:

d1 = A sinc([tex]\pi[/tex] r)

where A is a constant
AND

d2 = B sinc([tex]\pi[/tex] z)

where B is a constant
And: z = l + r * cos([tex]\theta[/tex])

where l is a constant

NOTE: THIS IS NOT A HOMEWORK QUESTION
 
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  • #2
redtree said:
How would I find the center of mass (COM) for a ring of variable density, where the variation in density can be described by a continuous mathematical equation.

The density at each location along the ring is described by a function (d) whose independent variables are radius (r) and angle ([tex]\theta[/tex]), i.e., polar coordinates.

Hi redtree! :smile:

(have a theta: θ and a pi: π :wink:)

Just change to x and y coordinates, and integrate in the usual way to find the x- and - components of the c.o.m. separately …

what do you get? :smile:
 
  • #3
Remember that the value of the radial variable of the center of mass is:
[tex]\hat{r}=\sqrt{\hat{x}^{2}+\hat{y}^{2}}[/tex] where [itex]\hat{x},\hat{y}[/itex] are the x and y-coordinates of the center of mass. Analogously for the value of the value pf the angular variable at the mass point.

There is no simplistic way to calculate these two values except by going through the intermediary x and y values.
 
  • #4
What is the formula (in x-y coordinates) for the center of mass of a ring of variable density?

I think the general formula is as follows:

R = [tex]\int[/tex] p(r) * r dV / [tex]\int[/tex] p(r) dV

In this case p(r) = d(r) = d1(r) + d2(r)
Where
d1(r) = A sinc(pi * (x2 + y2)(1/2))
d2(r) = B sinc(pi * ((l-x)2 + y2)(1/2))

So, how do I find "dV"?

This problem can also be restated as a "barycenter" problem:

r1 = a / (1 + m1/m2) and r2 = a / (1+m2/m1)

where
m1 is a function of d1(r)
m2 is a function of d2(r)
a = l.

However, even with this restatement, it seems that finding the COM for m2 is not straightforward.
 
  • #5
redtree said:
So, how do I find "dV"?

dV is dxdydz :wink:

(or, for a 2-dimensional mass, you'd use dA = dxdy)
 

FAQ: Center of mass of a ring of variable density

What is the center of mass of a ring of variable density?

The center of mass of a ring of variable density is the point at which the mass of the ring is evenly distributed. It is the point around which the ring will rotate if it is suspended from that point.

How is the center of mass of a ring of variable density calculated?

The center of mass of a ring of variable density can be calculated by taking the integral of the density function over the entire ring. This integral is divided by the total mass of the ring to get the position of the center of mass.

How does the density of a ring affect its center of mass?

The density of a ring can affect its center of mass by shifting the center of mass towards the denser areas of the ring. This means that the location of the center of mass will vary depending on the distribution of density within the ring.

What happens to the center of mass of a ring of variable density if the density distribution is symmetrical?

If the density distribution of a ring is symmetrical, the center of mass will be located at the geometric center of the ring. This means that the center of mass will be equidistant from all points on the ring.

Can the center of mass of a ring of variable density be outside of the physical boundaries of the ring?

Yes, it is possible for the center of mass to be located outside of the physical boundaries of the ring. This can happen if the density distribution is not symmetrical and is shifted towards one side of the ring, causing the center of mass to also shift towards that side.

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